Showing Visitor Messages 1 to 2 of 2
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a] PTHH:MgO+2HCl=MgCl2+H2O
PTHH:Mg+ 2HCl= MgCl2 + H2
PT :24g 2mol 22,4L
De :?g ?mol 4,48L
b] khoi luong Mg trong hon hop là:
mMg=4,48.24:22,4=4,8[g]
khoi luong MgO trong hon hop là:
mMgO=8,8-4,8=4[g]
C]PTHH: MgO + 2HCl= MgCl2 + H2O
PT :40g 2mol
de :4g ?mol
PTHH: Mg+ 2HCl = MgCl2+ H2
PT: 24g 2mol
de: 4,8g ?mol
So mol cua HCl tham gia phan ung la:
nHCl=[4.2:40]+[4,8.2:24]=0,6[mol]
The tich HCl can dung la:
V[HCl]=n:M=0,6:2=0,3[ml]
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Mg + HCl = MgCl2 + H2 (1)
MgO + HCl = MgCl2 + H2O (2)
n(H2) = 4.48/22.4 = 0.2(mol)
(1) => n(Mg) = n(H2) = 0.2(mol)
=> m(Mg) = 0.2x24 = 4.8(g)
=> m(MgO) = 8.8 - 4.8 = 4(g)
=> n(MgO) = 0.1(mol)
(2) => n(HCl) = 2x0.1 =- 0.2(mol)
(1) => n(HCl) = 2x0.2 = 0.4(mol)
=> n(HCl) = 0.6(mol)
nên m(HCl) = 0.6x36.5 = 21.9(g)
=> V(HCl) = m/d = 21.9/1.19 =?
